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The table gives the heat of combustion in kJ g⁻¹ for a number of different fuels - HSC - SSCE Chemistry - Question 6 - 2003 - Paper 1

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The table gives the heat of combustion in kJ g⁻¹ for a number of different fuels. | Fuel | Heat of combustion (kJ g⁻¹) | |-------------|---------------------... show full transcript

Worked Solution & Example Answer:The table gives the heat of combustion in kJ g⁻¹ for a number of different fuels - HSC - SSCE Chemistry - Question 6 - 2003 - Paper 1

Step 1

Identify the fuel with heat of combustion that corresponds to 2016 kJ mol⁻¹

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Answer

To calculate the heat of combustion in kJ mol⁻¹ for each fuel, we need to multiply the heat of combustion in kJ g⁻¹ by the molar mass of the respective fuel:

  1. Molar Mass Calculation:

    • Methanol (CH₃OH): 12.01 + 3(1.008) + 16.00 = 32.04 g/mol
    • Ethanol (C₂H₅OH): 2(12.01) + 6(1.008) + 16.00 = 46.08 g/mol
    • Propanol (C₃H₇OH): 3(12.01) + 8(1.008) + 16.00 = 60.10 g/mol
    • Petrol (C₈H₁₈): 8(12.01) + 18(1.008) = 114.23 g/mol
  2. Heat of Combustion Calculation for Each Fuel:

    • Methanol: 22.7extkJg1imes32.04extg/mol=727.0588extkJmol122.7 ext{ kJ g}^{-1} imes 32.04 ext{ g/mol} = 727.0588 ext{ kJ mol}^{-1}
    • Ethanol: 29.6extkJg1imes46.08extg/mol=1361.0048extkJmol129.6 ext{ kJ g}^{-1} imes 46.08 ext{ g/mol} = 1361.0048 ext{ kJ mol}^{-1}
    • Propanol: 33.6extkJg1imes60.10extg/mol=2016.36extkJmol133.6 ext{ kJ g}^{-1} imes 60.10 ext{ g/mol} = 2016.36 ext{ kJ mol}^{-1}
    • Petrol: 47.8extkJg1imes114.23extg/mol=5460.4586extkJmol147.8 ext{ kJ g}^{-1} imes 114.23 ext{ g/mol} = 5460.4586 ext{ kJ mol}^{-1}

From this calculation, Propanol yields an approximate value of 2016 kJ mol⁻¹.

Step 2

Select the correct answer from the options

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Answer

The correct answer is (C) Propanol, as it matches the calculated heat of combustion of 2016 kJ mol⁻¹.

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