The structure of a compound is shown - HSC - SSCE Chemistry - Question 6 - 2020 - Paper 1

To determine the preferred IUPAC name of the given compound, follow these steps:

1. Identify the longest carbon chain: The structure contains three carbon atoms in a straight chain. Therefore, the base name is 'propan'.

2. Number the carbon chain: Numbering should start from the end nearest to the substituents. In this case, numbering from the right gives:

   • 1st carbon: OH group (alcohol)
   • 2nd carbon: Fluorine (F)
   • 3rd carbon: three Bromine (Br) substituents.

3. Identify and name the substituents: The compound contains:

   • One hydroxyl (OH) group, which is the highest priority functional group and thus should be placed as '2-ol'.
   • One fluorine group, which must be mentioned as '2-fluoro'.
   • Three bromine atoms, indicated as '3,3,3-tribromo'.

4. Construct the IUPAC name: Based on the above, the name combines it all in the correct order, giving '3,3,3-tribromo-2-fluoropropan-1-ol' where:

   • Tribromo comes first (highest substituent count),
   • Then fluorine, followed by the base chain and functional group.

5. Final IUPAC Name: Therefore, the full preferred IUPAC name for the compound is 3,3,3-tribromo-2-fluoropropan-1-ol, which corresponds to option D.