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A 5.30 g sample of an alkali metal hydroxide was dissolved in water - HSC - SSCE Chemistry - Question 28 - 2021 - Paper 1

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A 5.30 g sample of an alkali metal hydroxide was dissolved in water. After mixing with excess Cu(NO3)2, the precipitate was collected, dried, measured and found to h... show full transcript

Worked Solution & Example Answer:A 5.30 g sample of an alkali metal hydroxide was dissolved in water - HSC - SSCE Chemistry - Question 28 - 2021 - Paper 1

Step 1

Identify the alkali metal hydroxide.

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Answer

Given that the precipitate formed is Cu(OH)2, we can infer that the alkali metal hydroxide must correspond to an OH- ion from an alkali metal, which typically includes lithium (Li), sodium (Na), potassium (K), rubidium (Rb), and cesium (Cs). Thus, we can conclude that we are working with potassium hydroxide (KOH) since it is the most common alkali metal hydroxide that corresponds to the formation of Cu(OH)2.

Step 2

Mass of Cu(OH)2.

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Answer

The mass of the precipitate obtained is given as 4.61 g.

Step 3

Calculation of moles of Cu(OH)2 formed.

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To find the moles of Cu(OH)2 formed, we use the molar mass of Cu(OH)2, which is calculated as:

Molar mass of Cu(OH)2 = 63.55 g/mol (Cu) + 2 × (16.00 g/mol (O) + 1.01 g/mol (H)) = 63.55 g/mol + 2 × 17.01 g/mol = 63.55 g/mol + 34.02 g/mol = 97.57 g/mol.

Moles of Cu(OH)2 = mass / molar mass = 4.61 g / 97.57 g/mol ≈ 0.0472 mol.

Step 4

Balanced chemical equation.

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The balanced equation for the reaction can be written as:

Cu(NO3)2(aq) + 2 KOH(aq) → Cu(OH)2(s) + 2 KNO3(aq).

This equation shows that copper(II) nitrate reacts with potassium hydroxide to form the precipitate copper(II) hydroxide and potassium nitrate.

Step 5

Conclusion.

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Answer

Thus, it can be concluded that the alkali metal hydroxide is potassium hydroxide (KOH), confirmed by calculations and the balanced equation.

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