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Consider the following endothermic reaction taking place in a closed vessel - HSC - SSCE Chemistry - Question 14 - 2016 - Paper 1

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Consider the following endothermic reaction taking place in a closed vessel. $$N_2O_4(g) \rightleftharpoons 2NO_2(g)$$ Which of the following actions would cause m... show full transcript

Worked Solution & Example Answer:Consider the following endothermic reaction taking place in a closed vessel - HSC - SSCE Chemistry - Question 14 - 2016 - Paper 1

Step 1

Adding a catalyst

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Answer

Adding a catalyst does not affect the position of equilibrium; it only speeds up the rate at which equilibrium is reached. Therefore, this action will not increase the production of N2O4N_2O_4.

Step 2

Decreasing the volume

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Answer

Decreasing the volume of a gaseous reaction shifts the equilibrium towards the side with fewer moles of gas. In this reaction, the left side (N2O4N_2O_4) has 1 mole, while the right side has 2 moles. Therefore, decreasing the volume will favor the formation of N2O4N_2O_4, resulting in more being produced.

Step 3

Decreasing the pressure

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Answer

Decreasing the pressure in a system shifts the equilibrium towards the side with more moles of gas. Hence, it will favor the formation of NO2NO_2, resulting in less N2O4N_2O_4 being produced.

Step 4

Increasing the temperature

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Answer

Since the reaction is endothermic, increasing the temperature will shift the equilibrium to favor the formation of the products, which is NO2NO_2, rather than N2O4N_2O_4. Thus, this action will not result in more N2O4N_2O_4 being produced.

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