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Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation - HSC - SSCE Chemistry - Question 10 - 2006 - Paper 1

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Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation. $$P_2O_5(s) + 3H_2O(l) \rightarrow 2H_3PO_4(aq)$$ Phosphoric ac... show full transcript

Worked Solution & Example Answer:Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation - HSC - SSCE Chemistry - Question 10 - 2006 - Paper 1

Step 1

Calculate moles of phosphorus pentoxide

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Answer

To find the number of moles of phosphorus pentoxide (P₂O₅), we use the formula:

n=mMn = \frac{m}{M}

Where:

  • nn = number of moles
  • mm = mass (1.42 g)
  • MM = molar mass of P₂O₅ (=2×31.00+5×16.00=141.94gmol1= 2 \times 31.00 + 5 \times 16.00 = 141.94 g mol^{-1})

Thus,

n=1.42141.940.0100 moln = \frac{1.42}{141.94} \approx 0.0100 \text{ mol}

Step 2

Determine moles of phosphoric acid produced

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Answer

From the balanced chemical equation, 1 mol of P₂O₅ produces 2 mol of H₃PO₄. Hence:

Moles of H3PO4=2×0.01000.0200 mol\text{Moles of } H_3PO_4 = 2 \times 0.0100 \approx 0.0200 \text{ mol}

Step 3

Calculate moles of sodium hydroxide needed

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Answer

From the equation, 1 mol of H₃PO₄ reacts with 3 mol of NaOH. Therefore, the moles of NaOH required are:

Moles of NaOH=3×0.0200=0.0600 mol\text{Moles of } NaOH = 3 \times 0.0200 = 0.0600 \text{ mol}

Step 4

Calculate the volume of sodium hydroxide solution needed

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Answer

Using the concentration of NaOH (C=0.30mol L1C = 0.30 \, \text{mol L}^{-1}), we can find the volume using:

C=nVC = \frac{n}{V}

Where VV is the volume in liters. Rearranging gives:

V=nC=0.06000.30=0.20LV = \frac{n}{C} = \frac{0.0600}{0.30} = 0.20 \, \text{L}

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