Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation - HSC - SSCE Chemistry - Question 10 - 2006 - Paper 1
Question 10
Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation.
$$P_2O_5(s) + 3H_2O(l) \rightarrow 2H_3PO_4(aq)$$
Phosphoric ac... show full transcript
Worked Solution & Example Answer:Phosphorus pentoxide reacts with water to form phosphoric acid according to the following equation - HSC - SSCE Chemistry - Question 10 - 2006 - Paper 1
Step 1
Calculate moles of phosphorus pentoxide
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Answer
To find the number of moles of phosphorus pentoxide (P₂O₅), we use the formula:
n=Mm
Where:
n = number of moles
m = mass (1.42 g)
M = molar mass of P₂O₅ (=2×31.00+5×16.00=141.94gmol−1)
Thus,
n=141.941.42≈0.0100 mol
Step 2
Determine moles of phosphoric acid produced
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Answer
From the balanced chemical equation, 1 mol of P₂O₅ produces 2 mol of H₃PO₄. Hence:
Moles of H3PO4=2×0.0100≈0.0200 mol
Step 3
Calculate moles of sodium hydroxide needed
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Answer
From the equation, 1 mol of H₃PO₄ reacts with 3 mol of NaOH. Therefore, the moles of NaOH required are:
Moles of NaOH=3×0.0200=0.0600 mol
Step 4
Calculate the volume of sodium hydroxide solution needed
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Answer
Using the concentration of NaOH (C=0.30mol L−1), we can find the volume using:
C=Vn
Where V is the volume in liters. Rearranging gives: