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A pH 3.0 solution of HCl(aq) is diluted by adding water to produce a pH 5.0 solution - HSC - SSCE Chemistry - Question 15 - 2013 - Paper 1

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A pH 3.0 solution of HCl(aq) is diluted by adding water to produce a pH 5.0 solution. Which row in the following table correctly identifies an appropriate volume of... show full transcript

Worked Solution & Example Answer:A pH 3.0 solution of HCl(aq) is diluted by adding water to produce a pH 5.0 solution - HSC - SSCE Chemistry - Question 15 - 2013 - Paper 1

Step 1

Identify the pH values of the solutions

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Answer

The initial solution has a pH of 3.0, meaning it has a high concentration of H<sub>3</sub>O<sup>+</sup> ions. The target solution has a pH of 5.0, which indicates a much lower concentration of H<sub>3</sub>O<sup>+</sup> ions.

Step 2

Calculate the concentration change

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Answer

The pH scale is logarithmic. The difference between pH 3.0 and pH 5.0 is 2 units. Since each unit change in pH represents a tenfold difference in concentration, we can express the change as: [H3O+]final=105M[H_3O^+]_{final} = 10^{-5} \, M. [H3O+]initial=103M[H_3O^+]_{initial} = 10^{-3} \, M. This means for every mole of H<sub>3</sub>O<sup>+</sup>, we need to dilute it to achieve the reduction in concentration.

Step 3

Determine the dilution factor

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Answer

The dilution factor can be calculated as: D=[H3O+]initial[H3O+]final=103105=100.D = \frac{[H_3O^+]_{initial}}{[H_3O^+]_{final}} = \frac{10^{-3}}{10^{-5}} = 100. This indicates that we need to dilute the initial solution by a factor of 100.

Step 4

Identify the appropriate volumes from the table

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Answer

Using the dilution factor of 100, if we take 1 mL of the original solution, we would need to add 99 mL of water to achieve a total volume of 100 mL. However, among the choices given:

  • Choice (C) with 10 mL of original solution and 990 mL of water is appropriate. When combined, it gives a total of 1000 mL, which follows the dilution factor correctly. Therefore, the correct answer is (C).

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