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The table shows the heat of combustion for four compounds - HSC - SSCE Chemistry - Question 11 - 2013 - Paper 1

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The table shows the heat of combustion for four compounds. | Compound | Heat of combustion (kJ mol⁻¹) | |----------|-------------------------------| | CO | 23... show full transcript

Worked Solution & Example Answer:The table shows the heat of combustion for four compounds - HSC - SSCE Chemistry - Question 11 - 2013 - Paper 1

Step 1

Identify the compound with the highest heat of combustion

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Answer

From the table, we see the heat of combustion values for the four compounds:

  • CO: 233 kJ mol⁻¹
  • CH₄: 890 kJ mol⁻¹
  • C₂H₂: 1300 kJ mol⁻¹
  • C₂H₆: 1560 kJ mol⁻¹

The compound with the highest heat of combustion is C₂H₆, which has a heat of combustion of 1560 kJ mol⁻¹.

Step 2

Determine the energy produced by 1.00 g of C₂H₆

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Answer

To find the energy produced by burning 1.00 g of C₂H₆, we first need the molar mass of C₂H₆:

  • Molar mass of C₂H₆ = 2(12.01 g/mol for C) + 6(1.008 g/mol for H) = 30.07 g/mol.

Next, we calculate the moles in 1.00 g of C₂H₆:

extmolesofC2H6=1.00extg30.07extg/mol0.0332extmol ext{moles of C₂H₆} = \frac{1.00 ext{ g}}{30.07 ext{ g/mol}} \approx 0.0332 ext{ mol}

Finally, we calculate the total energy produced:

extEnergy=extmoles×heat of combustion=0.0332extmol×1560extkJ/mol51.79extkJ ext{Energy} = ext{moles} \times \text{heat of combustion} = 0.0332 ext{ mol} \times 1560 ext{ kJ/mol} \approx 51.79 ext{ kJ}

Thus, burning 1.00 g of C₂H₆ would produce approximately 51.79 kJ of energy.

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