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The molar heat of combustion of pentan-1-ol is 2800 kJ mol⁻¹ - HSC - SSCE Chemistry - Question 17 - 2011 - Paper 1

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The molar heat of combustion of pentan-1-ol is 2800 kJ mol⁻¹. A quantity of pentan-1-ol was combusted, generating 108 kJ of heat. What mass of pentan-1-ol was combu... show full transcript

Worked Solution & Example Answer:The molar heat of combustion of pentan-1-ol is 2800 kJ mol⁻¹ - HSC - SSCE Chemistry - Question 17 - 2011 - Paper 1

Step 1

Calculate Moles of Pentan-1-ol Combusted

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Answer

To find the number of moles of pentan-1-ol that were combusted, we can use the formula:

n=qΔHn = \frac{q}{\Delta H}

where:

  • nn is the number of moles,
  • qq is the heat released (108 kJ),
  • ΔH\Delta H is the molar heat of combustion (2800 kJ/mol).

Substituting the values, we have: n=108kJ2800kJ mol1=0.03857moln = \frac{108\, \text{kJ}}{2800\, \text{kJ mol}^{-1}} = 0.03857\, \text{mol}

Step 2

Calculate Mass of Pentan-1-ol

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Answer

Next, we need to find the mass of pentan-1-ol using the number of moles we've calculated.

The molar mass of pentan-1-ol (C₅H₁₂O) is approximately:

  • C: 12.01 g/mol × 5 = 60.05 g/mol
  • H: 1.008 g/mol × 12 = 12.096 g/mol
  • O: 16.00 g/mol × 1 = 16.00 g/mol
  • Total molar mass = 60.05 + 12.096 + 16.00 = 88.146 g/mol

Using the formula:

mass=n×Molar Mass\text{mass} = n \times \text{Molar Mass}

we can substitute the values: mass=0.03857mol×88.146g mol13.40g\text{mass} = 0.03857\, \text{mol} \times 88.146\, \text{g mol}^{-1} \approx 3.40\, \text{g}

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