The mass spectrum and carbon-13 NMR for an organic compound are shown - HSC - SSCE Chemistry - Question 12 - 2021 - Paper 1
Question 12
The mass spectrum and carbon-13 NMR for an organic compound are shown.
Mass spectrum
Relative intensity
100
80
60
40
20
0
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Worked Solution & Example Answer:The mass spectrum and carbon-13 NMR for an organic compound are shown - HSC - SSCE Chemistry - Question 12 - 2021 - Paper 1
Step 1
Which compound could produce the two spectra?
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Answer
To determine which compound produces the provided mass spectrum and carbon-13 NMR, we need to analyze both spectra.
Analyzing the Mass Spectrum
Peak Identification: Observe the major peaks in the mass spectrum. The peaks at m/z 42, 55, and 98 are notable, suggesting possible fragments or molecular ion signals.
Fragmentation Patterns: The m/z values can help infer the presence of functional groups or structural characteristics in the compound.
Analyzing the Carbon-13 NMR
Chemical Shifts: The NMR shows peaks at specific ppm values. A common peak near 0-40 ppm typically indicates alkane or methyl groups, while higher values indicate carbonyl or aromatic signals.
Peak Splitting and Integration: Evaluate the number of unique carbon environments, which will reveal how many different types of carbons are present in the compound.
Comparing with Options A-D
Compare the observed m/z ratios and peaks in both the mass spectrum and carbon-13 NMR against the proposed structures (A-D).
Identification
After evaluating all the options, the compound represented by option A matches the spectra. This indicates that the spectra are characteristic of the functional groups and fragmentation patterns present in option A.