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Sodium azide is used in automobile airbags to provide a source of nitrogen gas for rapid inflation in an accident - HSC - SSCE Chemistry - Question 19 - 2010 - Paper 1

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Sodium azide is used in automobile airbags to provide a source of nitrogen gas for rapid inflation in an accident. The equation shows the production of nitrogen gas ... show full transcript

Worked Solution & Example Answer:Sodium azide is used in automobile airbags to provide a source of nitrogen gas for rapid inflation in an accident - HSC - SSCE Chemistry - Question 19 - 2010 - Paper 1

Step 1

Calculate the number of moles of N2 gas required for 40 L at 100 kPa and 0°C

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Answer

Using the Ideal Gas Law, PV = nRT:

Where:

  • P = 100 kPa = 100,000 Pa
  • V = 40 L = 0.040 m³
  • R = 8.314 J/(K·mol)
  • T = 0°C = 273.15 K

Rearranging the equation to find n:

n=PVRTn = \frac{PV}{RT}

Substituting the values in: n=(100000)(0.040)(8.314)(273.15)n = \frac{(100000)(0.040)}{(8.314)(273.15)}

Calculating: n1.78extmolesofN2n \approx 1.78 ext{ moles of N2}

Step 2

Determine the moles of NaN3 needed

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Answer

From the balanced equation, 2 moles of NaN3 produce 3 moles of N2.

Using the ratio: nNaN3=nN2×23n_{NaN3} = n_{N2} \times \frac{2}{3}

Substituting the value of moles of N2: nNaN3=1.78×231.19extmolesofNaN3n_{NaN3} = 1.78 \times \frac{2}{3} \approx 1.19 ext{ moles of NaN3}

Step 3

Calculate the mass of sodium azide required

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Answer

The molar mass of NaN3 is:

  • Na: 22.99 g/mol
  • N: 14.01 g/mol

Thus, the molar mass of NaN3: MNaN3=22.99+(3×14.01)=65.02extg/molM_{NaN3} = 22.99 + (3 \times 14.01) = 65.02 ext{ g/mol}

Now, calculating the mass: mass=n×MNaN3\text{mass} = n \times M_{NaN3}

Substituting the moles of NaN3: mass=1.19×65.0277.4extg\text{mass} = 1.19 \times 65.02 \approx 77.4 ext{ g}

Therefore, rounding up, the closest answer is 76 g.

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