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The heat of combustion of butan-1-ol is 2676 kJ mol<sup>-1</sup> - HSC - SSCE Chemistry - Question 3 - 2005 - Paper 1

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The heat of combustion of butan-1-ol is 2676 kJ mol<sup>-1</sup>. What is the value of the heat of combustion in kJ g<sup>-1</sup>? (A) 30.41 (B) 36.10 (C) 44.60 (D)... show full transcript

Worked Solution & Example Answer:The heat of combustion of butan-1-ol is 2676 kJ mol<sup>-1</sup> - HSC - SSCE Chemistry - Question 3 - 2005 - Paper 1

Step 1

Calculate the molar mass of butan-1-ol

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Answer

The molar mass of butan-1-ol (C<sub>4</sub>H<sub>10</sub>O) is calculated as follows:

  • Carbon (C): 4 × 12.01 g/mol = 48.04 g/mol
  • Hydrogen (H): 10 × 1.01 g/mol = 10.10 g/mol
  • Oxygen (O): 1 × 16.00 g/mol = 16.00 g/mol

Thus, the total molar mass is:

M=48.04+10.10+16.00=74.14extg/molM = 48.04 + 10.10 + 16.00 = 74.14 ext{ g/mol}

Step 2

Convert heat of combustion to kJ g<sup>-1</sup>

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Answer

To find the heat of combustion in kJ g<sup>-1</sup>, we use the formula:

extHeatofcombustion(kJg−1)=2676extkJmol−174.14extgmol−1 ext{Heat of combustion (kJ g}^{-1}\text{)} = \frac{2676 ext{ kJ mol}^{-1}}{74.14 ext{ g mol}^{-1}}

Calculating this gives:

Heat of combustion≈36.10extkJg−1\text{Heat of combustion} \approx 36.10 ext{ kJ g}^{-1}

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