A solution contains three cations, Ba<sup>2+</sup>, Cu<sup>2+</sup> and Pb<sup>2+</sup> - HSC - SSCE Chemistry - Question 22 - 2013 - Paper 1
Question 22
A solution contains three cations, Ba<sup>2+</sup>, Cu<sup>2+</sup> and Pb<sup>2+</sup>. The flow chart indicates the plan used to confirm the identity of these cati... show full transcript
Worked Solution & Example Answer:A solution contains three cations, Ba<sup>2+</sup>, Cu<sup>2+</sup> and Pb<sup>2+</sup> - HSC - SSCE Chemistry - Question 22 - 2013 - Paper 1
Step 1
Name Precipitate 2.
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Answer
Precipitate 2 is Barium Sulfate.
Step 2
Write a balanced net ionic equation for the formation of Precipitate 1.
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Answer
The balanced net ionic equation for the formation of Precipitate 1 (which is likely to be Lead(II) Chloride) is:
Pb2+(aq)+2Cl−(aq)→PbCl2(s)
Step 3
Suggest a test and the expected result that would confirm the identity of the metal cation remaining in Filtrate 2.
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Answer
To identify the metal cation in Filtrate 2 (which is likely to be Copper), one can suggest a suitable test:
Test: Add a few drops of ammonia solution to the filtrate.
Expected Result: A blue-colored solution indicates the presence of Copper(II) ions, confirming its identity.
