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History and Geography are two of the subjects students may decide to study - HSC - SSCE Mathematics Advanced - Question 14 - 2020 - Paper 1

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History and Geography are two of the subjects students may decide to study. For a group of 40 students, the following is known. - 7 students study neither History n... show full transcript

Worked Solution & Example Answer:History and Geography are two of the subjects students may decide to study - HSC - SSCE Mathematics Advanced - Question 14 - 2020 - Paper 1

Step 1

A student is chosen at random. By using a Venn diagram, or otherwise, find the probability that the student studies both History and Geography.

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Answer

To solve this, we first determine the number of students studying each subject and those studying neither.

  1. Total number of students: 40

  2. Students studying neither: 7

    Therefore, students studying at least one subject:

    407=3340 - 7 = 33

  3. Let HH be the number of students studying History, and GG be the number of students studying Geography:

    • Students studying History: 20
    • Students studying Geography: 18

    We can denote the number of students studying both subjects as xx.

    Using the principle of inclusion-exclusion:

    H+Gx=33H + G - x = 33

    Plugging in the values: 20+18x=3320 + 18 - x = 33 38x=3338 - x = 33 x=5x = 5

  4. The probability that a student studies both History and Geography is given by:

    P(HextandG)=x40=540=18P(H ext{ and } G) = \frac{x}{40} = \frac{5}{40} = \frac{1}{8}

Step 2

A student is chosen at random. Given that the student studies Geography, what is the probability that the student does NOT study History?

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Answer

Using the information from part (a):

We have:

  • Total students studying Geography: 18
  • Students studying both History and Geography: 5

Total students studying only Geography:

Gonly=185=13G_{only} = 18 - 5 = 13

The probability that a student studies Geography does not study History is:

P(not HG)=GonlyG=1318P(\text{not } H | G) = \frac{G_{only}}{G} = \frac{13}{18}

Step 3

Two different students are chosen at random, one after the other. What is the probability that the first student studies History and the second student does NOT study History?

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Answer

For the first student, we know:

  • Number of students studying History: 20
  • Total students: 40

The probability that the first student studies History is:

P(H)=2040=12P(H) = \frac{20}{40} = \frac{1}{2}

For the second student:

  • After the first student has been chosen, there are now 39 students left.
  • If the first student studied History, then 19 students remain studying History and 20 students do not study History.

So, the probability that the second student does not study History is:

P(not H)=2039P(\text{not } H) = \frac{20}{39}

Thus, the combined probability of both events occurring is:

P(H)×P(not H)=12×2039=1039P(H) \times P(\text{not } H) = \frac{1}{2} \times \frac{20}{39} = \frac{10}{39}

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