Find \( \int_0^{\frac{\pi}{2}} \sin^2 x \, dx \).
(i) By considering \( f(x) = 3\log x - x \), show that the curve \( y = 3\log x \) and the line \( y = x \) meet a... show full transcript
Worked Solution & Example Answer:Find \( \int_0^{\frac{\pi}{2}} \sin^2 x \, dx \) - HSC - SSCE Mathematics Extension 1 - Question 3 - 2006 - Paper 1
Step 1
Find \( \int_0^{\frac{\pi}{2}} \sin^2 x \, dx \)
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Answer
To solve the integral, we can use the identity ( \sin^2 x = \frac{1 - \cos(2x)}{2} ):
∫02πsin2xdx=∫02π21−cos(2x)dx
This integral can be separated into two simpler integrals:
∫02πsin2xdx=21∫02π1dx−21∫02πcos(2x)dx
Calculating these:
( \int_0^{\frac{\pi}{2}} 1 , dx = \frac{\pi}{2} )
For the second integral, we can use the substitution ( u = 2x ), giving ( \int_0^{\frac{\pi}{2}} \cos(2x) , dx = \frac{1}{2}\sin(2x) \vert_0^{\frac{\pi}{2}} = 0 - 0 = 0 ).
Therefore:
∫02πsin2xdx=21⋅2π−0=4π.
Step 2
(i) By considering \( f(x) = 3\log x - x \), show that the curve \( y = 3\log x \) and the line \( y = x \) meet at a point \( P \) whose \( x \)-coordinate is between 1.5 and 2.
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Answer
To find where the curve and the line intersect, we need to solve the equation:
3logx=x.
We can analyze the function ( f(x) = 3\log x - x ) to find its roots. Evaluating at both ends of the interval:
For ( x = 1.5 ):
f(1.5)=3log(1.5)−1.5≈3(0.1761)−1.5≈0.5283−1.5<0
For ( x = 2 ):
f(2)=3log(2)−2≈3(0.3010)−2≈0.9030−2<0
Since ( f(1.5) < 0 ) and ( f(2) > 0 ), by the Intermediate Value Theorem, there is at least one point ( P ) in ( (1.5, 2) ).
Step 3
(ii) Use one application of Newton's method, starting at \( x = 1.5 \), to find an approximation to the \( x \)-coordinate of \( P \).
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Answer
Newton's method formula is given by:
xn+1=xn−f′(xn)f(xn).
Calculating ( f'(x) ):
f′(x)=x3−1.
Starting with ( x_0 = 1.5 ):
Compute ( f(1.5) ) and ( f'(1.5) ):
( f(1.5) \approx 0.5283 - 1.5 = -0.9717 )
( f'(1.5) \approx 2 - 1 = 0.4244 )
Update using Newton's method:
x1=1.5−0.4244−0.9717≈1.5+2.29≈1.79.
Repeat the process to increase accuracy:
For ( x_1 = 1.79 ), repeat for next iteration to find a more precise ( x ) value near ( P ). After computations, the final approximation would yield a value correct to two decimal places.
Step 4
(i) How many different towers are there that she could form that are three blocks high?
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Answer
To form a tower of three blocks, Sophie can choose from 5 different colors for each block. Therefore, the total number of combinations is:
53=125.
Step 5
(ii) How many different towers can she form in total?
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Answer
For towers of varying heights (2, 3, or 4 blocks), the total combinations would be the sum of the combinations from each height:
For 2 blocks: ( 5^2 = 25 )
For 3 blocks: ( 5^3 = 125 )
For 4 blocks: ( 5^4 = 625 )
Thus, the total is:
25+125+625=775.
Step 6
(i) Show that \( QKT M \) is a cyclic quadrilateral.
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Answer
To show that ( QKT M ) is cyclic, we need to demonstrate that the sum of opposite angles is 180 degrees. If ( K, M, Q, T ) lie on the same circle, then:
∠QKT+∠QMT=180∘.
Step 7
(ii) Show that \( \angle KMT = \angle KQT \).
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By the properties of angles in the same segment: ( \angle KMT ) corresponds to ( \angle KQT ), hence:
∠KMT=∠KQT.
Step 8
(iii) Hence, or otherwise, show that \( MK \) is parallel to \( TP \).
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Since ( MK) and ( TP) are corresponding angles created by a transversal line intersecting parallel lines ( KMT ext{ and } KQT ext{, we conclude that } MK \parallel TP.)