A given function $f(x)$ has an inverse $f^{-1}(x)$ - HSC - SSCE Mathematics Extension 1 - Question 9 - 2022 - Paper 1
Question 9
A given function $f(x)$ has an inverse $f^{-1}(x)$.
The derivatives of $f(x)$ and $f^{-1}(x)$ exist for all real numbers $x$.
The graphs $y = f(x)$ and $y = f^{-... show full transcript
Worked Solution & Example Answer:A given function $f(x)$ has an inverse $f^{-1}(x)$ - HSC - SSCE Mathematics Extension 1 - Question 9 - 2022 - Paper 1
Step 1
A. All points of intersection lie on the line $y = x$.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is true for all points of intersection if we remember that for a function and its inverse, they reflect across the line y=x. Thus, every point of intersection must satisfy f(x)=f−1(x), which occurs along the line.
Step 2
B. None of the points of intersection lie on the line $y = x$.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is false because, as previously discussed, points of intersection will lie on the line y=x.
Step 3
C. At no point of intersection are the tangents to the graphs parallel.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is likely true; for two graphs that are reflections of each other, their tangents would have slopes that are negative reciprocals of each other, which implies they cannot be parallel.
Step 4
D. At no point of intersection are the tangents to the graphs perpendicular.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is false. If the slopes of tangents are negative reciprocals at points of intersection, then they are perpendicular.