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Maria starts at the origin and walks along all of the vector $2 extbf{i} + 3 extbf{j}$, then walks along all of the vector $3 extbf{i} - 2 extbf{j}$ and finally along all of the vector $4 extbf{i} - 3 extbf{j}$ - HSC - SSCE Mathematics Extension 1 - Question 4 - 2020 - Paper 1

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Maria-starts-at-the-origin-and-walks-along-all-of-the-vector-$2-extbf{i}-+-3-extbf{j}$,-then-walks-along-all-of-the-vector-$3-extbf{i}---2-extbf{j}$-and-finally-along-all-of-the-vector-$4-extbf{i}---3-extbf{j}$-HSC-SSCE Mathematics Extension 1-Question 4-2020-Paper 1.png

Maria starts at the origin and walks along all of the vector $2 extbf{i} + 3 extbf{j}$, then walks along all of the vector $3 extbf{i} - 2 extbf{j}$ and finally alon... show full transcript

Worked Solution & Example Answer:Maria starts at the origin and walks along all of the vector $2 extbf{i} + 3 extbf{j}$, then walks along all of the vector $3 extbf{i} - 2 extbf{j}$ and finally along all of the vector $4 extbf{i} - 3 extbf{j}$ - HSC - SSCE Mathematics Extension 1 - Question 4 - 2020 - Paper 1

Step 1

Calculate the resultant vector after walking along $2\textbf{i} + 3\textbf{j}$

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Answer

The first vector is ( \textbf{A} = 2\textbf{i} + 3\textbf{j} ). After moving along this vector, Maria's position becomes ( \textbf{R_1} = \textbf{A} = (2, 3) ).

Step 2

Calculate the resultant vector after walking along $3\textbf{i} - 2\textbf{j}$

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Answer

The second vector is ( \textbf{B} = 3\textbf{i} - 2\textbf{j} ). Now adding this to the current position: ( \textbf{R_2} = \textbf{R_1} + \textbf{B} = (2 + 3, 3 - 2) = (5, 1) ).

Step 3

Calculate the resultant vector after walking along $4\textbf{i} - 3\textbf{j}$

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Answer

The third vector is ( \textbf{C} = 4\textbf{i} - 3\textbf{j} ). Now adding this to the current position: ( \textbf{R_3} = \textbf{R_2} + \textbf{C} = (5 + 4, 1 - 3) = (9, -2) ).

Step 4

Determine the final distance from the origin

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Answer

To find the distance from the origin to the final position ( \textbf{R_3} = (9, -2) ), we use the distance formula: d=(x2+y2)=(92+(2)2)=(81+4)=85.d = \sqrt{(x^2 + y^2)} = \sqrt{(9^2 + (-2)^2)} = \sqrt{(81 + 4)} = \sqrt{85}. Thus, the distance from the origin is ( \sqrt{85} ).

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