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Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive - HSC - SSCE Mathematics Extension 1 - Question 10 - 2016 - Paper 1

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Consider-the-polynomial-$p(x)-=-ax^3-+-bx^2-+-cx---6$-with-$a$-and-$b$-positive-HSC-SSCE Mathematics Extension 1-Question 10-2016-Paper 1.png

Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive. Which graph could represent $p(x)$?

Worked Solution & Example Answer:Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive - HSC - SSCE Mathematics Extension 1 - Question 10 - 2016 - Paper 1

Step 1

Identify Characteristics of the Polynomial

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Answer

The polynomial p(x)=ax3+bx2+cx6p(x) = ax^3 + bx^2 + cx - 6 is a cubic polynomial since its highest degree is 3. Given that a>0a > 0 and b>0b > 0, we can determine the overall behavior of the graph in the interval of positive and negative values for xx.

Step 2

Behavior of the Graph as $x o ext{infinity}$ and $x o - ext{infinity}$

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Answer

As xoextinfinityx o ext{infinity}, the term ax3ax^3 dominates, leading the graph to rise to extinfinity ext{infinity}. As xoextinfinityx o - ext{infinity}, ax3ax^3 also dominates, making the graph fall to extinfinity- ext{infinity}. This suggests that the ends of the graph will point upwards.

Step 3

Determine the Roots of the Polynomial

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Answer

The polynomial has at least one real root. This can be inferred from the Intermediate Value Theorem, which states that since the polynomial is continuous, it must cross the x-axis at least once.

Step 4

Choose the Correct Graph

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Answer

Given that the polynomial has the described behaviors, the graph that correctly represents this behavior is Graph (A), which starts low for negative x-values, rises to cross the x-axis, and ends high for positive x-values.

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