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Which diagram best represents the solution set of $x^2 - 2x - 3 \geq 0$? A - HSC - SSCE Mathematics Extension 1 - Question 1 - 2020 - Paper 1

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Question 1

Which-diagram-best-represents-the-solution-set-of-$x^2---2x---3-\geq-0$?--A-HSC-SSCE Mathematics Extension 1-Question 1-2020-Paper 1.png

Which diagram best represents the solution set of $x^2 - 2x - 3 \geq 0$? A. B. C. D.

Worked Solution & Example Answer:Which diagram best represents the solution set of $x^2 - 2x - 3 \geq 0$? A - HSC - SSCE Mathematics Extension 1 - Question 1 - 2020 - Paper 1

Step 1

Solve the inequality $x^2 - 2x - 3 \geq 0$

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Answer

First, we can rewrite the equation as follows:

x22x3=0x^2 - 2x - 3 = 0

Next, we factor the quadratic expression:

(x3)(x+1)=0(x - 3)(x + 1) = 0

Setting each factor equal to zero gives us the critical points:

  1. x3=0x=3x - 3 = 0 \Rightarrow x = 3
  2. x+1=0x=1x + 1 = 0 \Rightarrow x = -1

These critical points will help us determine the intervals to test for the inequality.

Step 2

Test intervals

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Answer

The critical points split the number line into three intervals:

  1. (,1)(-\infty, -1)
  2. (1,3)(-1, 3)
  3. (3,)(3, \infty)

We can test one point from each interval to determine where the inequality holds:

  • For the interval (,1)(-\infty, -1), choose x=2x = -2: (2)22(2)3=4+43=50(-2)^2 - 2(-2) - 3 = 4 + 4 - 3 = 5 \geq 0 (True)

  • For the interval (1,3)(-1, 3), choose x=0x = 0: 022(0)3=3<00^2 - 2(0) - 3 = -3 < 0 (False)

  • For the interval (3,)(3, \infty), choose x=4x = 4: 422(4)3=1683=504^2 - 2(4) - 3 = 16 - 8 - 3 = 5 \geq 0 (True)

From this testing, we find that the solution set is intervals (,1](-\infty, -1] and [3,)[3, \infty).

Step 3

Select the correct diagram

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Answer

The diagrams representing the solution set (,1][3,)(-\infty, -1] \cup [3, \infty) must include shaded regions at 1-1 and 33 with arrows continuing to the left and right. Therefore, the correct choice is:

A.

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