(a) Sketch the graph of $y = 3 ext{cos}^{-1}(2x)$ - HSC - SSCE Mathematics Extension 1 - Question 2 - 2003 - Paper 1
Question 2
(a) Sketch the graph of $y = 3 ext{cos}^{-1}(2x)$. Your graph must clearly indicate the domain and the range.
(b) Find $\frac{d}{dx} (x \tan^{-1} x)$.
(c) Evaluate... show full transcript
Worked Solution & Example Answer:(a) Sketch the graph of $y = 3 ext{cos}^{-1}(2x)$ - HSC - SSCE Mathematics Extension 1 - Question 2 - 2003 - Paper 1
Step 1
Sketch the graph of $y = 3\text{cos}^{-1}(2x)$
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Answer
To sketch the graph of y=3cos−1(2x), we first determine the domain and range:
Domain: The inverse cosine function is defined for −1≤2x≤1, leading to −0.5≤x≤0.5.
Range: The range of cos−1(x) is from 0 to π. Thus, multiplying by 3, the range of y becomes [0,3π].
Next, we plot the function, ensuring it reflects these characteristics.
Step 2
Find $\frac{d}{dx} (x \tan^{-1} x)$
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Answer
To differentiate xtan−1x, we use the product rule:
Let u=x and v=tan−1(x), where:
dxdu=1,
dxdv=1+x21.
Using the product rule:
dxd(uv)=udxdv+vdxdu
We get:
dxd(xtan−1x)=x⋅1+x21+tan−1(x)⋅1.