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The direction field for a differential equation is given on page 1 of the Question 12 Writing Booklet - HSC - SSCE Mathematics Extension 1 - Question 12 - 2021 - Paper 1

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The direction field for a differential equation is given on page 1 of the Question 12 Writing Booklet. The graph of a particular solution to the differential equati... show full transcript

Worked Solution & Example Answer:The direction field for a differential equation is given on page 1 of the Question 12 Writing Booklet - HSC - SSCE Mathematics Extension 1 - Question 12 - 2021 - Paper 1

Step 1

The direction field for a differential equation is given on page 1 of the Question 12 Writing Booklet.

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Answer

To sketch the graph of the particular solution that passes through point P, ensure the curve aligns with the direction field. The graph should reflect the behavior suggested by the direction field, maintaining stability and direction at equilibrium points.

Step 2

After 8 minutes, the temperature of the water is 10°C.

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Answer

Starting with the equation rac{dT}{dt} = k(T - 25) We separate the variables and integrate: rac{1}{T - 25} dT = k dt Integrating both sides yields: extlnT25=kt+C ext{ln}|T - 25| = kt + C To find C, we can use the initial condition T(0) = 5, leading to: C=extln525=extln(20)C = ext{ln} |5 - 25| = ext{ln}(20) When solving for T at t = 8, set T = 10: 1025=20e8k10 - 25 = 20e^{8k} Resulting in: e^{8k} = - rac{15}{20} From this, k can be solved. Then to find t when T = 20°C, we repeat similar steps to arrive at an approximate t value near 6 minutes.

Step 3

Sketch the graph of T as a function of t.

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The graph of T as a function of t will asymptotically approach the room temperature of 25°C, with an initial temperature of 5°C. It will pass through (0, 5), and rise to 20°C, reflecting a moderate upward curve as it approaches the limit.

Step 4

Use mathematical induction to prove that 1/(1 × 2 × 3) + 1/(2 × 3 × 4) + ⋯ + 1/(n(n + 1)(n + 2)) = 1/(2(n)(n + 2)) for all integers n ≥ 1.

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We first prove the base case for n = 1. ext{LHS} = rac{1}{1 imes 2 imes 3} = rac{1}{6} And for n = 1, ext{RHS} = rac{1}{2(1)(1 + 2)} = rac{1}{6} Assuming true for n = k, we show: 1/(1×2×3)+1/(2×3×4)+...+1/(k(k+1)(k+2))extholdstrueforn=k+1.1/(1 × 2 × 3) + 1/(2 × 3 × 4) + ... + 1/(k(k + 1)(k + 2)) ext{ holds true for n = k + 1.} This leads to manipulation of the fractions accordingly to demonstrate equality.

Step 5

Sketch the graph of y = f(x) showing the x- and y-intercepts.

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Answer

To sketch the graph of the function f(x) = 4 - (1 - x^2)², identify x-intercepts by setting f(x) = 0 and solve for x. The y-intercept can be found by evaluating f(0). Plot these intercepts and analyze the behavior by checking the derivative for increasing or decreasing sections.

Step 6

Find the equation of the inverse function, f^(-1)(x), and state its domain.

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Answer

Begin with the equation y = 4 - (1 - x^2)². Solve for x in terms of y, leading to x=1extorx=2extvariousrootsderivedfromrearranging.x = 1 ext{ or } x = 2 - ext{various roots derived from rearranging.} The domain of the inverse should reflect that of the original function, limited to the y-values calculated via f.

Step 7

Sketch the graph of y = f^(-1)(x).

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Answer

The graph of the inverse function should mirror that of the original function. Identify key features based on the intersection of the function with y = x line, swapping the axes appropriately.

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