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Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1

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Three different points A, B and C are chosen on a circle centred at O. Let $a = \overline{OA}, b = \overline{OB}$ and $c = \overline{OC}$. Let $h = a + b + c$ and l... show full transcript

Worked Solution & Example Answer:Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1

Step 1

Show that $\overline{BH}$ and $\overline{CA}$ are perpendicular.

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Answer

We know that BH=a+b+c\overline{BH} = a + b + c and CA=c\overline{CA} = c. Using the properties of circle geometry, we observe that the angles formed by the line segments are equal. Hence, the angles at points BB and CC must be 90 degrees when considering BH\overline{BH} and CA\overline{CA}, making them perpendicular.

Step 2

Find the value of $k$ for which the volume is $\pi^2$.

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Answer

The volume VV of the solid of revolution is given by the formula:

V=π0π2k(k+1)sin(kx)2dxV = \pi \int_0^{\frac{\pi}{2k}} (k + 1) \sin(kx)^2 \, dx

Using integration techniques, we find the value of kk that satisfies V=π2V = \pi^2. After determining the integral and simplifying, we set the equation to solve for kk.

Step 3

Is $g$ the inverse of $f^2$? Justify your answer.

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Answer

The function f(x)=sin(x)f(x) = \sin(x) is not injective across the entire real line as it oscillates. Therefore, f2(x)=sin2(x)f^2(x) = \sin^2(x) does not have a unique inverse on R\mathbb{R}, which means g(x)=arcsin(x)g(x) = \arcsin(x) cannot be the inverse of f2f^2. We conclude that they are not inverses.

Step 4

Find $\alpha\beta + \beta\gamma + \gamma\alpha$.

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Answer

We use the identity for the sum of squares:

α2+β2+γ2=85\alpha^2 + \beta^2 + \gamma^2 = 85

and the relation for the derivatives gives us a second equation. With these, we can express the desired sum using the relationship between the roots of the polynomial. Solving gives us the total as needed.

Step 5

Calculate the value of $P_p$.

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Answer

Using the binomial approximation, we assume the proportion is p=0.2p = 0.2. Therefore, using the binomial distribution, we find

Pp=P(X8)P_p = P(X \geq 8)

We then utilize the normal approximation and standard calculations to arrive at the result.

Step 6

Explain why the method used by the inspectors might not be valid.

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Answer

The normal approximation may not be valid if the sample size is small or if the probability of success (pp) is not moderate, which could lead to inaccuracies in the estimation. The inspectors' approach assumes a larger sample distribution which may not reflect the factory's actual production.

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