The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D - HSC - SSCE Mathematics Extension 1 - Question 14 - 2018 - Paper 1
Question 14
The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D. The bisectors at A and B intersect at the point P. The bisectors at A and D me... show full transcript
Worked Solution & Example Answer:The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D - HSC - SSCE Mathematics Extension 1 - Question 14 - 2018 - Paper 1
Step 1
Show that PQRS is a cyclic quadrilateral
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To demonstrate that quadrilateral PQRS is cyclic, we must show that the opposite angles are supplementary.
Step 1: Angle Relationships
Let
rac{1}{2} A = a,
rac{1}{2} B = b,
rac{1}{2} C = c,
rac{1}{2} D = d.
Step 2: Sum of Opposite Angles
By the properties of angle bisectors and angles in a cyclic quadrilateral, we find:
Angle PQR + Angle PSR = 180°
b+d=180° (from angles at B and D)
Similarly,
Angle QRS + Angle RSP = 180°
a+c=180° (from angles at A and C)
Thus, since opposite angles sum to 180°, we can conclude that PQRS is a cyclic quadrilateral.
Step 2
By considering the expansions of (1 + (1 + x)^y) and (2 + y^x), show that
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
We start by expanding both expressions:
Expansion of (1 + (1 + x)^y)
Using the binomial theorem, the expansion is:
ext{Coefficient of } x^{r} = {y race r}
Expansion of (2 + y^x)
Similarly, this can be expanded:
ext{Coefficient of } x^{r} = {r race r}
There are 23 people who have applied to be selected for a committee of 4 people.
The selection process starts with Selector A choosing a group of at least 4 people from the 23 people who applied.
Selector B then chooses the 4 people to be on the committee from the group Selector A has chosen.
In how many ways could this selection process be carried out?
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Step 1: Choose at least 4 people
Selector A can choose between 4 to 23 people:
extTotalways=∑k=423(k23)
Step 2: Choose 4 from the chosen group
After selector A's choice of k people, Selector B has:
(4k) ways to choose the committee .
Final Count
To find the total number of ways:
extTotal=∑k=423(k23)(4k)
Evaluating the Sum
This calculation can be performed using combinatorial identities to arrive at the final total.