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Question 15
In the set of integers, let P be the proposition: 'If k + 1 is divisible by 3, then k^3 + 1 is divisible by 3'. (i) Prove that the proposition P is true. (ii) Wri... show full transcript
Step 1
Answer
To prove the proposition P, we start by assuming that k + 1 is divisible by 3. This implies that there exists an integer j such that:
We can express k as:
Next, we calculate k^3 + 1:
Expanding this using the binomial theorem gives:
It is evident that:
Since 9j^3 - 9j^2 + 3j is an integer, this shows that k^3 + 1 is divisible by 3. Therefore, we conclude that the proposition P is true.
Step 2
Step 3
Answer
The converse of the proposition P is:
'If k^3 + 1 is divisible by 3, then k + 1 is divisible by 3.'
To evaluate whether this converse is true, consider a counterexample. Let k = 2:
For k = 2, we have:
Now, consider k = 1:
This demonstrates that the converse is false in general since it does not hold for all integer values of k.
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