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A monic polynomial, $f(x)$, of degree 3 with real coefficients has 3 and $2 + i$ as two of its roots - HSC - SSCE Mathematics Extension 2 - Question 4 - 2024 - Paper 1

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A monic polynomial, $f(x)$, of degree 3 with real coefficients has 3 and $2 + i$ as two of its roots. Which of the following could be $f(x)$? A. $f(x) = x^3 - 7x^2... show full transcript

Worked Solution & Example Answer:A monic polynomial, $f(x)$, of degree 3 with real coefficients has 3 and $2 + i$ as two of its roots - HSC - SSCE Mathematics Extension 2 - Question 4 - 2024 - Paper 1

Step 1

Identify the Roots

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Answer

Since the polynomial has real coefficients and one of the roots is the complex number 2+i2 + i, its conjugate 2i2 - i must also be a root. Therefore, the roots of the polynomial f(x)f(x) are 33, 2+i2 + i, and 2i2 - i.

Step 2

Form the Polynomial

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Answer

To construct the polynomial f(x)f(x), we will use the fact that it can be expressed as: f(x)=(x3)((x(2+i))(x(2i)))f(x) = (x - 3)((x - (2 + i))(x - (2 - i)))

The quadratic factor can be calculated as: (x(2+i))(x(2i))=(x2)2+1=x24x+5.(x - (2 + i))(x - (2 - i)) = (x - 2)^2 + 1 = x^2 - 4x + 5.
Thus, the polynomial can be rewritten as: f(x)=(x3)(x24x+5)f(x) = (x - 3)(x^2 - 4x + 5).

Step 3

Expand the Polynomial

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Next, we can expand this expression: f(x)=(x3)(x24x+5)f(x) = (x - 3)(x^2 - 4x + 5)

Expanding gives: =x34x2+5x3x2+12x15= x^3 - 4x^2 + 5x - 3x^2 + 12x - 15 =x37x2+17x15.= x^3 - 7x^2 + 17x - 15.

Step 4

Identify the Correct Option

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Answer

From our expansion, we have: f(x)=x37x2+17x15,f(x) = x^3 - 7x^2 + 17x - 15, which corresponds with option B.

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