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Let R be the region in the complex plane defined by 1 < Re(z) ≤ 3 and \frac{\pi}{6} ≤ Arg(z) < \frac{\pi}{3} - HSC - SSCE Mathematics Extension 2 - Question 1 - 2022 - Paper 1

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Let-R-be-the-region-in-the-complex-plane-defined-by--1-<-Re(z)-≤-3-and--\frac{\pi}{6}-≤-Arg(z)-<-\frac{\pi}{3}-HSC-SSCE Mathematics Extension 2-Question 1-2022-Paper 1.png

Let R be the region in the complex plane defined by 1 < Re(z) ≤ 3 and \frac{\pi}{6} ≤ Arg(z) < \frac{\pi}{3}. Which diagram best represents the region R?

Worked Solution & Example Answer:Let R be the region in the complex plane defined by 1 < Re(z) ≤ 3 and \frac{\pi}{6} ≤ Arg(z) < \frac{\pi}{3} - HSC - SSCE Mathematics Extension 2 - Question 1 - 2022 - Paper 1

Step 1

Define the constraints for the region R

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Answer

The region R is defined by two constraints:

  1. The real part of the complex number z (denoted as Re(z)) must lie between 1 and 3:

    1<Re(z)31 < \text{Re}(z) \leq 3

  2. The argument of z (denoted as Arg(z)) must lie between \frac{\pi}{6} and \frac{\pi}{3}:

    π6Arg(z)<π3\frac{\pi}{6} \leq \text{Arg}(z) < \frac{\pi}{3}

Step 2

Sketch the region based on the constraints

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Answer

To visualize this region:

  • Start by drawing vertical lines at Re(z) = 1 and Re(z) = 3.

  • The vertical line at Re(z) = 1 is not included (open boundary), while the line at Re(z) = 3 is included (closed boundary).

  • Next, for the argument:

    • The angle \frac{\pi}{6} corresponds to 30 degrees, and \frac{\pi}{3} corresponds to 60 degrees, creating a wedge in the upper half of the complex plane.
  • The intersection of these two regions defines R.

Step 3

Select the correct diagram

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Answer

Based on the analysis above, the diagram that best represents the region R is diagram A, which includes the specified boundaries and angles.

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