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Which of the following is equal to $e^{ar{z}}$, where $z = x + iy$ with $x$ and $y$ real numbers? A - HSC - SSCE Mathematics Extension 2 - Question 8 - 2024 - Paper 1

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Which-of-the-following-is-equal-to-$e^{ar{z}}$,-where-$z-=-x-+-iy$-with-$x$-and-$y$-real-numbers?--A-HSC-SSCE Mathematics Extension 2-Question 8-2024-Paper 1.png

Which of the following is equal to $e^{ar{z}}$, where $z = x + iy$ with $x$ and $y$ real numbers? A. $\bar{e}$ B. $e^{-z}$ C. $e^{2x} e^{\bar{z}}$ D. $e^{-2z} e^{\... show full transcript

Worked Solution & Example Answer:Which of the following is equal to $e^{ar{z}}$, where $z = x + iy$ with $x$ and $y$ real numbers? A - HSC - SSCE Mathematics Extension 2 - Question 8 - 2024 - Paper 1

Step 1

Identify the expression

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Answer

The expression we need to analyze is e^{ar{z}}. Since z=x+iyz = x + iy, we have ar{z} = x - iy. Thus, we want to find an equivalent expression for exiye^{x - iy}.

Step 2

Apply Euler's formula

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Answer

Using Euler's formula, we know that ea+bi=ea(extcos(b)+iextsin(b))e^{a + bi} = e^a ( ext{cos}(b) + i ext{sin}(b)). Substituting a=xa = x and b=yb = -y, we get: e^{ar{z}} = e^{x - iy} = e^x ( ext{cos}(-y) + i ext{sin}(-y)) = e^x ( ext{cos}(y) - i ext{sin}(y)).

Step 3

Compare with options

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Answer

Now, we can compare this result with the given options:

  • A. eˉ\bar{e} does not match.
  • B. ez=exiy=exeiye^{-z} = e^{-x - iy} = e^{-x} e^{-iy}. Hence, this is not equivalent either.
  • C. e2xezˉ=e2xexiy=e3xeiye^{2x} e^{\bar{z}} = e^{2x} e^{x - iy} = e^{3x} e^{-iy}, which is incorrect.
  • D. e2zezˉ=e2(x+iy)exiy=e2xe2iyexiye^{-2z} e^{\bar{z}} = e^{-2(x + iy)} e^{x - iy} = e^{-2x} e^{-2iy} e^{x - iy}. This simplifies to exe3iye^{-x} e^{-3iy}, which is also not valid.

After evaluating all the options, it is clear that the most suitable answer is A.

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