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As a projectile of mass $m$ kilograms travels through air, it experiences a frictional force - HSC - SSCE Mathematics Extension 2 - Question 8 - 2022 - Paper 1

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As a projectile of mass $m$ kilograms travels through air, it experiences a frictional force. The magnitude of this force is proportional to the square of the speed ... show full transcript

Worked Solution & Example Answer:As a projectile of mass $m$ kilograms travels through air, it experiences a frictional force - HSC - SSCE Mathematics Extension 2 - Question 8 - 2022 - Paper 1

Step 1

Identify the forces acting on the projectile

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Answer

The forces acting on the projectile include:

  1. The gravitational force downwards, given by: Fg=mgj^\vec{F}_g = -mg\hat{j}, where j^\hat{j} is the unit vector upward.
  2. The frictional force, which opposes the motion and is given by: Ff=kv2v^\vec{F}_f = -k v^2 \hat{v}, where v^\hat{v} is the unit vector in the direction of velocity.

Step 2

Apply Newton's second law

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Answer

According to Newton's second law, the net force acting on the projectile is equal to the mass of the projectile multiplied by its acceleration:

Fnet=ma\vec{F}_{net} = m\vec{a}

Thus, we can express the net force as:

Fnet=Fg+Ff=mgj^kv2v^\vec{F}_{net} = \vec{F}_g + \vec{F}_f = -mg\hat{j} - k v^2 \hat{v}

Step 3

Combine the forces to form the equation of motion

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Answer

Substituting into Newton's second law gives:

mgj^kv2v^=ma-mg\hat{j} - k v^2 \hat{v} = m\vec{a}

This equation captures the motion of the projectile, where the terms on the left represent the forces and the term on the right represents the mass times the acceleration.

Step 4

Choose the correct model from the options

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Answer

The derived equation matches option B:

(mgj^kv2v^=ma)(-mg \hat{j} - k v^2 \hat{v} = m \vec{a})

Hence, the correct answer is B.

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