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Consider the proposition: ‘If $2^n - 1$ is not prime, then $n$ is not prime$^2$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2020 - Paper 1

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Consider-the-proposition:--‘If-$2^n---1$-is-not-prime,-then-$n$-is-not-prime$^2$-HSC-SSCE Mathematics Extension 2-Question 10-2020-Paper 1.png

Consider the proposition: ‘If $2^n - 1$ is not prime, then $n$ is not prime$^2$. Given that each of the following statements is true, which statement disproves the... show full transcript

Worked Solution & Example Answer:Consider the proposition: ‘If $2^n - 1$ is not prime, then $n$ is not prime$^2$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2020 - Paper 1

Step 1

A. $2^5 - 1$ is prime

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Answer

This statement indicates that when n=5n=5, 251=312^5 - 1 = 31, which is indeed a prime number. However, this does not disprove the original proposition, as it confirms the case where nn can be prime and still have 2n12^n - 1 as prime.

Step 2

B. $2^6 - 1$ is divisible by 9

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Answer

Calculating 2612^6 - 1 gives us 6363, which is divisible by 99. This means that when n=6n=6, 2612^6 - 1 is not a prime number (since it's composite). However, n=6n=6 is not a prime number either, which does not contradict the original statement.

Step 3

C. $2^7 - 1$ is prime

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Answer

Evaluating this, we find that 271=1272^7 - 1 = 127, which is a prime number. Like in option A, this does not invalidate the proposition, since when n=7n=7, it upholds the condition of the statement.

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