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Suppose that $f(x)$ is a non-zero odd function - HSC - SSCE Mathematics Extension 2 - Question 8 - 2017 - Paper 1

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Suppose that $f(x)$ is a non-zero odd function. Which of the functions below is also odd? A. $f(x^2) ext{cos } x$ B. $f(f(x))$ C. $f(x^3) ext{sin } x$ D. $f(x^2) -... show full transcript

Worked Solution & Example Answer:Suppose that $f(x)$ is a non-zero odd function - HSC - SSCE Mathematics Extension 2 - Question 8 - 2017 - Paper 1

Step 1

A. $f(x^2) \text{cos } x$

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Answer

To determine if this function is odd, we check:

f(x2)cos(x)=f(x2)cos(x)f(-x^2) \text{cos}(-x) = -f(x^2) \text{cos}(x)

Since f(x2)f(x^2) is an even function (as it depends on x2x^2) and extcosx ext{cos } x is even, the product is not odd.

Step 2

B. $f(f(x))$

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Answer

Since f(x)f(x) is an odd function, we check:

f(f(x))=f(f(x))=f(f(x))f(f(-x)) = f(-f(x)) = -f(f(x))

Thus, f(f(x))f(f(x)) is also odd.

Step 3

C. $f(x^3) \text{sin } x$

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Answer

Checking its oddness:

f(x3)sin(x)=f(x3)(extsin(x))=f(x3)sinxf(-x^3) \text{sin}(-x) = -f(x^3)(- ext{sin}(x)) = f(x^3) \text{sin} x

Here, f(x3)f(x^3) is odd and extsinx ext{sin } x is odd, therefore the product is odd.

Step 4

D. $f(x^2) - f(x)$

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Answer

Checking:

f((x2))f(x)=f(x2)+f(x)f(-(x^2)) - f(-x) = f(x^2) + f(x)

Since f(x2)f(x^2) is even and f(x)f(x) is odd, this does not yield an odd function.

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