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It is known that a particular complex number z is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1

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It is known that a particular complex number z is NOT a real number. Which of the following could be true for this number z? A. $ar{z} = iz$ B. $ar{z} = |z|$ C... show full transcript

Worked Solution & Example Answer:It is known that a particular complex number z is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1

Step 1

A. $ar{z} = iz$

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Answer

For a complex number z=x+iyz = x + iy where xx is the real part and yy is the imaginary part, the conjugate is given by ar{z} = x - iy. The equation ar{z} = iz translates to xiy=i(x+iy)x - iy = i(x + iy), which simplifies to xiy=y+ixx - iy = -y + ix. This system can lead to x=yx = -y and yy not being zero since zz is not real. Therefore, this statement can be true.

Step 2

B. $ar{z} = |z|$

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Answer

The modulus of zz is non-negative and is defined as z=extsqrt(x2+y2)|z| = ext{sqrt}(x^2 + y^2). Thus, ar{z} = |z| would imply xiy=extsqrt(x2+y2)x - iy = ext{sqrt}(x^2 + y^2) which cannot be true since yy is non-zero (as zz is not real). Therefore, this statement is false.

Step 3

C. Re($iz$) = Im($z$)

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If we write iziz as i(x+iy)=y+ixi(x + iy) = -y + ix, the real part Re(iziz) is y-y and the imaginary part Im(zz) is yy. For these to be equal, we have y=y-y = y, leading to y=0y = 0. This contradicts the condition that zz is not a real number. Therefore, this statement is false.

Step 4

D. Arg($ rac{z^3}{z}$) = Arg($z$)

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The expression simplifies to Arg(z2z^2), which is 2imesextArg(z)2 imes ext{Arg}(z). It can only equal Arg(zz) if Arg(zz) is zero, which would make zz real. Hence, this statement cannot be true either.

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