It is given that
$$|z - 1 + i| = 2.$$
What is the maximum possible value of
$$|z|?$$ - HSC - SSCE Mathematics Extension 2 - Question 7 - 2024 - Paper 1
Question 7
It is given that
$$|z - 1 + i| = 2.$$
What is the maximum possible value of
$$|z|?$$
Worked Solution & Example Answer:It is given that
$$|z - 1 + i| = 2.$$
What is the maximum possible value of
$$|z|?$$ - HSC - SSCE Mathematics Extension 2 - Question 7 - 2024 - Paper 1
Step 1
Find the expression of $|z|$
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Answer
Let z=x+yi, where x and y are real numbers. Then, we can rewrite the equation as:
∣z−(1−i)∣=2
This implies that the distance from the point (1,−1) in the complex plane to the point (x,y) is equal to 2.
Step 2
Geometric Interpretation
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Answer
This describes a circle centered at the point (1,−1) with a radius of 2. The equation can be expressed as:
(x−1)2+(y+1)2=4.
Step 3
Maximize $|z| = |x + yi|$
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Answer
To find the maximum value of ∣z∣, we need to maximize:
∣z∣=extdistancefromtheoriginto(x,y),
which is given by:
∣z∣=extsqrt(x2+y2).
The maximum distance occurs when the circle touches a line passing through the origin.
Step 4
Use Distance Formula
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Answer
Using the distance formula and considering the geometry involved, the maximum distance can be found when the line from the origin to (1,−1) is extended. The furthest point on the circle from the origin will be along this line, and we can use the Pythagorean theorem to evaluate the distance:
∣z∣=extdistance=2+extradius.
Therefore the maximum possible value of $|z| = 2 + ext{distance from origin to circle center} = 2 + ext{sqrt}(1^2 + (-1)^2) = 2 + ext{sqrt}(2) = 2 + ext{sqrt}(2).$$