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Multiplying a non-zero complex number by \( \frac{1 - i}{1 + i} \) results in a rotation about the origin on an Argand diagram - HSC - SSCE Mathematics Extension 2 - Question 5 - 2016 - Paper 1

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Multiplying a non-zero complex number by \( \frac{1 - i}{1 + i} \) results in a rotation about the origin on an Argand diagram. What is the rotation? (A) Clockwise... show full transcript

Worked Solution & Example Answer:Multiplying a non-zero complex number by \( \frac{1 - i}{1 + i} \) results in a rotation about the origin on an Argand diagram - HSC - SSCE Mathematics Extension 2 - Question 5 - 2016 - Paper 1

Step 1

Calculate the multiplication

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Answer

To find the rotation caused by multiplying a complex number by ( \frac{1 - i}{1 + i} ), we first compute this multiplication:

1i1+i=(1i)(1i)(1+i)(1i)=12i+i21i2=12i11+1=2i2=i\frac{1 - i}{1 + i} = \frac{(1 - i)(1 - i)}{(1 + i)(1 - i)} = \frac{1 - 2i + i^2}{1 - i^2} = \frac{1 - 2i - 1}{1 + 1} = \frac{-2i}{2} = -i

Step 2

Identify the angle of rotation

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Answer

The complex number ( -i ) can be represented in polar form. Each complex number can be written as ( re^{i\theta} ), where ( r ) is the modulus and ( \theta ) is the argument. Here, the modulus is 1 and the argument corresponds to the angle of a rotation:

  • The angle ( \theta = \frac{3\pi}{2} ) radians, which corresponds to a rotation of ( \frac{\pi}{2} ) radians in the clockwise direction.

Step 3

Final answer

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Answer

Thus, multiplying by ( \frac{1 - i}{1 + i} ) results in a clockwise rotation by ( \frac{\pi}{2} ), leading to the answer (B).

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