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What is the Cartesian equation of the line \( r = \left( \frac{1}{3} \right) + \lambda \left( -\frac{2}{4} \right) ? - HSC - SSCE Mathematics Extension 2 - Question 3 - 2020 - Paper 1

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What-is-the-Cartesian-equation-of-the-line-\(-r-=-\left(-\frac{1}{3}-\right)-+-\lambda-\left(--\frac{2}{4}-\right)-?-HSC-SSCE Mathematics Extension 2-Question 3-2020-Paper 1.png

What is the Cartesian equation of the line \( r = \left( \frac{1}{3} \right) + \lambda \left( -\frac{2}{4} \right) ?

Worked Solution & Example Answer:What is the Cartesian equation of the line \( r = \left( \frac{1}{3} \right) + \lambda \left( -\frac{2}{4} \right) ? - HSC - SSCE Mathematics Extension 2 - Question 3 - 2020 - Paper 1

Step 1

Determine the direction vector

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Answer

The line is given in the form ( r = \mathbf{a} + \lambda \mathbf{b} ), where ( \mathbf{a} ) is the point ( \left( \frac{1}{3}, 0 \right) ) and ( \mathbf{b} ) is the direction vector ( \left( -\frac{2}{4} \right) ). Simplifying the direction vector gives ( \left( -\frac{1}{2}, 1 \right) ).

Step 2

Find Cartesian coordinates

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Answer

To convert to Cartesian coordinates, we can express the components as follows:

[ x = \frac{1}{3} - \frac{1}{2} \lambda ] [ y = 0 + 1 \lambda ] Thus, substituting ( \lambda ) from the first equation into the second gives: [ \lambda = y ] [ x = \frac{1}{3} - \frac{1}{2} y ]

Step 3

Rearranging to find the equation

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Answer

Rearranging the expression for ( x ): [ \frac{1}{2} y = \frac{1}{3} - x ] Multiplying through by 2 results in: [ y = -2x + 1/3 ] To clear fractions, eliminate the denominator: [ 2y - 4x = 2/3 ] In simplified form, we identify the correct choice from the options.

Step 4

Identify correct option

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Answer

Comparing our derived equation ( y + 2x = 5 ) to the provided options, we select option C, which matches our rearranged equation.

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