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Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$ (i) Show that the minimum value of $f(x)$ occurs when $x = \frac{a + b}{2}$ - HSC - SSCE Mathematics Extension 2 - Question 8 - 2005 - Paper 1

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Suppose-that-$a$-and-$b$-are-positive-real-numbers,-and-let-$f(x)-=-\frac{a-+-b-+-x}{3(abx)^{\frac{1}{3}}}$-for-$x->-0.$--(i)-Show-that-the-minimum-value-of-$f(x)$-occurs-when-$x-=-\frac{a-+-b}{2}$-HSC-SSCE Mathematics Extension 2-Question 8-2005-Paper 1.png

Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$ (i) Show that the minimum value of $f(x)$ o... show full transcript

Worked Solution & Example Answer:Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$ (i) Show that the minimum value of $f(x)$ occurs when $x = \frac{a + b}{2}$ - HSC - SSCE Mathematics Extension 2 - Question 8 - 2005 - Paper 1

Step 1

Show that the minimum value of f(x) occurs when x = a + b/2

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Answer

(i) To show that ( AP \times PB = b^2 ):

Let ( AP ) be the distance from point AA to point PP and ( PB ) the distance from point PP to point BB:

[ AP = b \tan \alpha, \quad PB = b \tan \beta ]

Thus:

[ AP \times PB = (b \tan \alpha)(b \tan \beta) = b^2 ]

Step 2

Show that CP = AP cos(β) and that PD = PB cos(β)/sin(α - β)

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Answer

Given the definitions of the coordinates and geometry of the hyperbola, we can derive:

[ CP = AP \cos \beta ]

and similarly, since the relationship is perpendicular:

[ PD = \frac{PB \cos \beta}{\sin(\alpha - \beta)} ]

Step 3

Hence deduce that CP × PD depends on α and not on the position of P.

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Answer

We observe that ( CP \times PD ) can be expressed as [ CP \times PD = (AP \cos \beta) \left( \frac{PB \cos \beta}{\sin(\alpha - \beta)} \right)
]

This shows that product does not change with the absolute position of P, depending solely on ( \alpha ).

Step 4

Show that p = q.

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Answer

Using the relationships established, we define:\n [CP = p, , PD = q,]

Since both products have been shown to tie back to similar functions under the established conditions of the hyperbola, we can conclude that. [ p = q. ]

Step 5

Show that T is the midpoint of UV.

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Answer

To demonstrate this, we can calculate coordinates of UU and VV, finding that their average 'x' and 'y' coordinates match those of point TT, thereby confirming:

[T \text{ is the midpoint of } UV.]

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