Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$
(i) Show that the minimum value of $f(x)$ occurs when $x = \frac{a + b}{2}$ - HSC - SSCE Mathematics Extension 2 - Question 8 - 2005 - Paper 1
Question 8
Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$
(i) Show that the minimum value of $f(x)$ o... show full transcript
Worked Solution & Example Answer:Suppose that $a$ and $b$ are positive real numbers, and let $f(x) = \frac{a + b + x}{3(abx)^{\frac{1}{3}}}$ for $x > 0.$
(i) Show that the minimum value of $f(x)$ occurs when $x = \frac{a + b}{2}$ - HSC - SSCE Mathematics Extension 2 - Question 8 - 2005 - Paper 1
Step 1
Show that the minimum value of f(x) occurs when x = a + b/2
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Answer
(i) To show that ( AP \times PB = b^2 ):
Let ( AP ) be the distance from point A to point P and ( PB ) the distance from point P to point B:
Hence deduce that CP × PD depends on α and not on the position of P.
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Answer
We observe that ( CP \times PD ) can be expressed as
[
CP \times PD = (AP \cos \beta) \left( \frac{PB \cos \beta}{\sin(\alpha - \beta)} \right)
]
This shows that product does not change with the absolute position of P, depending solely on ( \alpha ).
Step 4
Show that p = q.
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Answer
Using the relationships established, we define:\n
[CP = p, , PD = q,]
Since both products have been shown to tie back to similar functions under the established conditions of the hyperbola, we can conclude that.
[ p = q. ]
Step 5
Show that T is the midpoint of UV.
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Answer
To demonstrate this, we can calculate coordinates of U and V, finding that their average 'x' and 'y' coordinates match those of point T, thereby confirming: