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The complex number $z$ is chosen so that $1, z, z^2, eq ext{...}, z^7$ form the vertices of the regular polygon shown - HSC - SSCE Mathematics Extension 2 - Question 1 - 2017 - Paper 1

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The-complex-number-$z$-is-chosen-so-that-$1,-z,-z^2,--eq--ext{...},-z^7$-form-the-vertices-of-the-regular-polygon-shown-HSC-SSCE Mathematics Extension 2-Question 1-2017-Paper 1.png

The complex number $z$ is chosen so that $1, z, z^2, eq ext{...}, z^7$ form the vertices of the regular polygon shown. Which polynomial equation has all of these ... show full transcript

Worked Solution & Example Answer:The complex number $z$ is chosen so that $1, z, z^2, eq ext{...}, z^7$ form the vertices of the regular polygon shown - HSC - SSCE Mathematics Extension 2 - Question 1 - 2017 - Paper 1

Step 1

Which polynomial equation has all of these complex numbers as roots?

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Answer

To find the polynomial equation that has the complex numbers 1,z,z2,ext...,z71, z, z^2, ext{...}, z^7 as roots, we note that these roots are the 7th roots of unity. The general form for finding roots of unity is given by the equation:

zn1=0z^n - 1 = 0

For the case of 7 roots, we have:

z71=0z^7 - 1 = 0

The correct answer is Option A: z71=0z^7 - 1 = 0. This polynomial has the required complex numbers as its roots.

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