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José takes out a loan of $9000 - HSC - SSCE Mathematics Standard - Question 13 - 2024 - Paper 1

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José takes out a loan of $9000. Simple interest is charged on the loan. The loan and the interest charged will be repaid by making monthly repayments of $300 over 4... show full transcript

Worked Solution & Example Answer:José takes out a loan of $9000 - HSC - SSCE Mathematics Standard - Question 13 - 2024 - Paper 1

Step 1

Calculate the total amount repaid

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Answer

The total amount repaid after 4 years can be calculated by multiplying the monthly payment by the total number of months. There are 4 years, and each year has 12 months, so the total months are:

4 years×12 months/year=48 months4 \text{ years} \times 12 \text{ months/year} = 48 \text{ months}

Thus, the total amount repaid is:

$300 per month×48 months=$14,400\$300 \text{ per month} \times 48 \text{ months} = \$14,400

Step 2

Calculate the total interest paid

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Answer

To find the total interest paid, subtract the initial loan amount from the total amount repaid:

Total Interest=Total Amount RepaidLoan Amount\text{Total Interest} = \text{Total Amount Repaid} - \text{Loan Amount}

Plugging in the numbers:

Total Interest=$14,400$9,000=$5,400\text{Total Interest} = \$14,400 - \$9,000 = \$5,400

Step 3

Calculate the simple interest rate per annum

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Answer

The simple interest can be calculated using the formula:

I=P×r×tI = P \times r \times t

Where:

  • I is the total interest
  • P is the principal amount (the loan)
  • r is the rate of interest per annum
  • t is the time in years

Rearranging for r:

r=IP×tr = \frac{I}{P \times t}

Substituting the values:

r=54009000×4=540036000=0.15r = \frac{5400}{9000 \times 4} = \frac{5400}{36000} = 0.15

Converting to a percentage:

r0.15×100%=15%r \approx 0.15 \times 100\% = 15\%

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