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The scores on an examination are normally distributed with a mean of 70 and a standard deviation of 6 - HSC - SSCE Mathematics Standard - Question 15 - 2019 - Paper 1

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The scores on an examination are normally distributed with a mean of 70 and a standard deviation of 6. Michael received a score on the examination between the lower ... show full transcript

Worked Solution & Example Answer:The scores on an examination are normally distributed with a mean of 70 and a standard deviation of 6 - HSC - SSCE Mathematics Standard - Question 15 - 2019 - Paper 1

Step 1

Determine the Lower Quartile (Q1)

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Answer

In a normal distribution, the lower quartile (Q1) corresponds to the 25th percentile. To find Q1, we can use the mean ( ar{x} = 70 ) and standard deviation ( extSD=6 ext{SD} = 6 ).

Using the z-score for the 25th percentile, approximately zextvalueextforQ1extis0.67449.z ext{ value} ext{ for } Q1 ext{ is } -0.67449.

Using the formula: Q1 = ar{x} + z imes ext{SD}

Substituting the values: Q1=70+(0.67449)imes6=704.04694extapproximately65.95Q1 = 70 + (-0.67449) imes 6 \\ = 70 - 4.04694 \\ ext{approximately } 65.95

Step 2

Determine the Upper Quartile (Q3)

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Answer

In the same way, the upper quartile (Q3) corresponds to the 75th percentile. The z-score for the 75th percentile is approximately zextvalueextforQ3extis0.67449.z ext{ value} ext{ for } Q3 ext{ is } 0.67449.

Using the formula: Q3 = ar{x} + z imes ext{SD}

Substituting the values: Q3=70+(0.67449)imes6=70+4.04694extapproximately74.05Q3 = 70 + (0.67449) imes 6 \\ = 70 + 4.04694 \\ ext{approximately } 74.05

Step 3

Identify the Shaded Region

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Answer

Michael's score lies between the lower quartile (approximately 65.95) and the upper quartile (approximately 74.05). Therefore, we need to identify the shaded region in the options that fall between these two values.

Thus, the correct answer is option A, which represents this range in the provided graph.

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