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If x = -2.531, what is the value of x² rounded to 2 decimal places? A - HSC - SSCE Mathematics Standard - Question 1 - 2024 - Paper 1

Question 1

If x = -2.531, what is the value of x² rounded to 2 decimal places? A. -6.41 B. -6.40 C. 6.40 D. 6.41

Worked Solution & Example Answer:If x = -2.531, what is the value of x² rounded to 2 decimal places? A - HSC - SSCE Mathematics Standard - Question 1 - 2024 - Paper 1

Step 1

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Answer

To find the value of x², we substitute the value of x into the equation:

$x^2 = (-2.531)^2$

Calculating this gives:

$x^2 = 6.404761561$

Step 2

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Answer

Now, we round 6.404761561 to two decimal places. Looking at the third decimal place (4), since it is less than 5, we do not round up. Thus:

$6.404761561 ext{ rounded to 2 decimal places is } 6.40$

Step 3

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101 rated

Answer

The value of x² rounded to 2 decimal places is 6.40. Therefore, the correct choice is:

C. 6.40

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