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Consider the diagram below - HSC - SSCE Mathematics Standard - Question 14 - 2021 - Paper 1

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Question 14

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Consider the diagram below. N | | A | | 25° | B --- E What is the true bearing of A from B? A. 025° B. 065° C. 115° D. 295°

Worked Solution & Example Answer:Consider the diagram below - HSC - SSCE Mathematics Standard - Question 14 - 2021 - Paper 1

Step 1

What is the true bearing of A from B?

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Answer

To determine the true bearing of point A from point B, we first recognize that bearings are measured clockwise from the North direction.

  1. From the diagram, point A is at a 25° angle from the North towards the East (E). This forms a clockwise angle from North to the line AB.

  2. Next, to find the bearing from point B to point A, we need to calculate the angle moving clockwise from point N through points E and then to point B.

  3. The bearing can thus be calculated as:

    extBearingfromBtoA=360°25°=335° ext{Bearing from B to A} = 360° - 25° = 335°

However, since we are looking for the bearing from A to B, we take:

extBearingfromAtoB=360°335°=25° ext{Bearing from A to B} = 360° - 335° = 25°

  1. Therefore, the true bearing of A from B is:

    • D. 295° (which is obtained by measuring the angle clockwise around back to the North direction from point A's position.)

Thus, the correct answer is option D: 295°.

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