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In glycolysis, the ATP yield per molecule of glucose is: 1 - VCE - SSCE Biology - Question 14 - 2019 - Paper 1

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In glycolysis, the ATP yield per molecule of glucose is: 1. 4 ATP produced and 2 ATP used for a net gain of 2 ATP. 2. 2 ATP produced and 4 ATP used for a net loss o... show full transcript

Worked Solution & Example Answer:In glycolysis, the ATP yield per molecule of glucose is: 1 - VCE - SSCE Biology - Question 14 - 2019 - Paper 1

Step 1

4 ATP produced and 2 ATP used for a net gain of 2 ATP.

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Answer

In glycolysis, two ATP molecules are invested during the energy investment phase, and four ATP molecules are produced in the energy payoff phase. Thus, the net gain of ATP is calculated as:

4extATPproduced2extATPused=2extATPnetgain4 ext{ ATP produced} - 2 ext{ ATP used} = 2 ext{ ATP net gain}

Therefore, this option is correct regarding ATP yield in glycolysis.

Step 2

2 ATP produced and 4 ATP used for a net loss of 2 ATP.

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Answer

This statement is incorrect as it suggests a loss of ATP, while glycolysis actually results in a net gain of ATP. Although two ATP are used, glycolysis yields four ATP, leading to a net gain of 2 ATP.

Step 3

36 to 38 ATP produced for a net gain of 2 ATP.

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Answer

This statement refers to the total ATP yield from cellular respiration, which includes glycolysis, the Krebs cycle, and the electron transport chain. The glycolysis step specifically produces a net of 2 ATP; further processes allow for the formation of an additional 34 to 36 ATP, but this is not solely attributed to glycolysis.

Step 4

36 to 38 ATP used for a net loss of 2 ATP.

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Answer

This statement is incorrect. Glycolysis does not result in using 36 to 38 ATP, nor does it result in a net loss. Instead, glycolysis primarily has a net gain of 2 ATP.

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