Photo AI

The results of the tests of three patients are given in the following table: | | Positive Control | Negative Control | Patient R | Patient S | Patient T | |-----------------|------------------|------------------|-----------|-----------|-----------| | Optical Density | 1.689 | 0.153 | 0.155 | 0.675 | 1.999 | Numbers are expressed as optical density at 450 nm - VCE - SSCE Biology - Question 25 - 2012 - Paper 1

Question icon

Question 25

The-results-of-the-tests-of-three-patients-are-given-in-the-following-table:--|-----------------|-Positive-Control-|-Negative-Control-|-Patient-R-|-Patient-S-|-Patient-T-|-|-----------------|------------------|------------------|-----------|-----------|-----------|-|-Optical-Density-|-1.689------------|-0.153------------|-0.155-----|-0.675-----|-1.999-----|--Numbers-are-expressed-as-optical-density-at-450-nm-VCE-SSCE Biology-Question 25-2012-Paper 1.png

The results of the tests of three patients are given in the following table: | | Positive Control | Negative Control | Patient R | Patient S | Patie... show full transcript

Worked Solution & Example Answer:The results of the tests of three patients are given in the following table: | | Positive Control | Negative Control | Patient R | Patient S | Patient T | |-----------------|------------------|------------------|-----------|-----------|-----------| | Optical Density | 1.689 | 0.153 | 0.155 | 0.675 | 1.999 | Numbers are expressed as optical density at 450 nm - VCE - SSCE Biology - Question 25 - 2012 - Paper 1

Step 1

A. patient R has not been exposed to HIV.

96%

114 rated

Answer

Patient R's optical density is 0.155, which is much lower than the cut-off value of 0.500, indicating that patient R has not been exposed to HIV.

Step 2

B. patient R has been exposed to the HIV antigen.

99%

104 rated

Answer

This statement is incorrect since patient R's optical density does not exceed the cut-off value, suggesting no exposure to the HIV antigen.

Step 3

C. patient S has responded to exposure to HIV by developing antibodies.

96%

101 rated

Answer

Patient S's optical density is 0.675, which is above 0.500. This suggests that patient S has developed antibodies in response to exposure to HIV.

Step 4

D. the positive control contained fewer HIV antibodies than the negative control.

98%

120 rated

Answer

This statement is false since the positive control (1.689) has a significantly higher optical density compared to the negative control (0.153), indicating it contains more antibodies.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;