The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation
HOCl(aq) + H⁺(aq) + Cl⁻(aq) ⇌ Cl₂(aq) + H₂O(l)
Which of the following, when added to a solution of NaOCl, would not raise the concentration of Cl₂ in the solution?
A - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1
Question 16
The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation
HOCl(aq) + H⁺(aq) + Cl⁻... show full transcript
Worked Solution & Example Answer:The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation
HOCl(aq) + H⁺(aq) + Cl⁻(aq) ⇌ Cl₂(aq) + H₂O(l)
Which of the following, when added to a solution of NaOCl, would not raise the concentration of Cl₂ in the solution?
A - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1
Step 1
NaCl
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Answer
Adding NaCl introduces more Cl⁻ ions into the solution, which can shift the equilibrium to produce more Cl₂, thus increasing its concentration.
Step 2
NaOH
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Answer
The addition of NaOH would increase the pH of the solution, affecting the equilibrium in a way that could potentially reduce the formation of Cl₂, thereby not raising its concentration.
Step 3
H₂SO₄
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Answer
H₂SO₄ contributes both H⁺ and SO₄²⁻ ions. The introduction of H⁺ ions would shift the equilibrium to produce more Cl₂ in solution, thus increasing its concentration.
Step 4
HOCl
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Answer
Adding HOCl will react in the equilibrium, but since it is already present, it will not increase the concentration of Cl₂ further. Therefore, the correct answer is B. NaOH, which would not raise the concentration of Cl₂.
