Photo AI

Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation - VCE - SSCE Chemistry - Question 10 - 2018 - Paper 1

Question icon

Question 10

Bioethanol,-C2H5OH,-is-produced-by-the-fermentation-of-glucose,-C6H12O6,-according-to-the-following-equation-VCE-SSCE Chemistry-Question 10-2018-Paper 1.png

Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation. C6H12O6(aq) → 2C2H5OH(aq) + 2CO2(g) The mass of C2H5O... show full transcript

Worked Solution & Example Answer:Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation - VCE - SSCE Chemistry - Question 10 - 2018 - Paper 1

Step 1

Step 1: Determine the molar mass of CO2

96%

114 rated

Answer

The molar mass of CO2 is calculated as follows:

  • Carbon (C): 12.01 g/mol
  • Oxygen (O): 16.00 g/mol

Thus, the molar mass of CO2 = 12.01 + 2(16.00) = 44.01 g/mol.

Step 2

Step 2: Calculate moles of CO2 produced

99%

104 rated

Answer

Using the mass of CO2 produced:

Number of moles of CO2 = ( \frac{\text{mass}}{\text{molar mass}} = \frac{5.68 \text{ g}}{44.01 \text{ g/mol}} \approx 0.129 \text{ mol} )

Step 3

Step 3: Use stoichiometry to find moles of C2H5OH produced

96%

101 rated

Answer

According to the reaction, 2 moles of C2H5OH are produced for every 2 moles of CO2:

So, moles of C2H5OH = moles of CO2 = 0.129 mol.

Step 4

Step 4: Calculate the mass of C2H5OH produced

98%

120 rated

Answer

The molar mass of C2H5OH is:

  • Carbon (C): 2 × 12.01 = 24.02 g/mol
  • Hydrogen (H): 6 × 1.008 = 6.048 g/mol
  • Oxygen (O): 1 × 16.00 = 16.00 g/mol

Thus, molar mass of C2H5OH = 24.02 + 6.048 + 16.00 = 46.068 g/mol.

Now, Mass of C2H5OH = moles × molar mass = 0.129 mol × 46.068 g/mol ≈ 5.94 g.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;