The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC) - VCE - SSCE Chemistry - Question 15 - 2022 - Paper 1
Question 15
The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC).
Which one of the fol... show full transcript
Worked Solution & Example Answer:The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC) - VCE - SSCE Chemistry - Question 15 - 2022 - Paper 1
Step 1
A. Cellular respiration is an endothermic reaction.
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Answer
This statement is incorrect. Cellular respiration is an exothermic reaction as it releases energy, not absorbs it.
Step 2
B. The products of cellular respiration are carbon and carbon dioxide.
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This statement is partially correct but misleading. The primary products of cellular respiration are carbon dioxide and water, not just carbon.
Step 3
C. Cellular respiration is a redox reaction because C₆H₁₂O₆ accepts electrons from oxygen.
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Answer
This statement is incorrect. In cellular respiration, glucose (C₆H₁₂O₆) is oxidized, meaning it loses electrons, while oxygen is reduced as it gains electrons.
Step 4
D. When one mole of oxygen is consumed in the reaction, 467.5 kJ of energy is released.
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Answer
This statement is accurate. During cellular respiration, the overall reaction releases energy, translating to a significant energy yield as molecules are broken down.
