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Carbon monoxide, water vapour, carbon dioxide and hydrogen were pumped into a sealed container that was maintained at a constant temperature of 200 °C - VCE - SSCE Chemistry - Question 9 - 2012 - Paper 1

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Carbon monoxide, water vapour, carbon dioxide and hydrogen were pumped into a sealed container that was maintained at a constant temperature of 200 °C. After 30 seco... show full transcript

Worked Solution & Example Answer:Carbon monoxide, water vapour, carbon dioxide and hydrogen were pumped into a sealed container that was maintained at a constant temperature of 200 °C - VCE - SSCE Chemistry - Question 9 - 2012 - Paper 1

Step 1

Determine the reaction quotient (Q)

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Answer

To analyze the rates of reactions, we first need to calculate the reaction quotient, Q. For a general reaction of the form:

aA+bBcC+dDaA + bB \rightleftharpoons cC + dD

The expression for Q is:

Q=[C]c[D]d[A]a[B]bQ = \frac{[C]^c [D]^d}{[A]^a [B]^b}

Substituting in the concentrations:

Q=[CO2]1[H2]2[CO]1[H2O]1=(2.0)1(2.0)2(0.1)1(0.1)1=2.0×4.00.1×0.1=8.00.01=800Q = \frac{[CO2]^1 [H2]^2}{[CO]^1 [H2O]^1} = \frac{(2.0)^1 (2.0)^2}{(0.1)^1 (0.1)^1} = \frac{2.0 \times 4.0}{0.1 \times 0.1} = \frac{8.0}{0.01} = 800

Step 2

Compare Q to K

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Answer

Given that the equilibrium constant K is 210 and Q is 800, we can see that Q > K. This indicates that the forward reaction is still occurring at a higher rate compared to the reverse reaction at the current set of conditions.

Step 3

Conclusion about the reaction rates

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Since Q > K, the rate of the forward reaction must be greater than the rate of the reverse reaction in order to reach equilibrium. Therefore, the correct statement is:

A. The rate of the forward reaction is greater than the rate of the reverse reaction.

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