If the equilibrium system were suddenly heated at constant volume at the five-minute mark, which one of the following changes would result?
A - VCE - SSCE Chemistry - Question 16 - 2016 - Paper 1
Question 16
If the equilibrium system were suddenly heated at constant volume at the five-minute mark, which one of the following changes would result?
A. The concentration of ... show full transcript
Worked Solution & Example Answer:If the equilibrium system were suddenly heated at constant volume at the five-minute mark, which one of the following changes would result?
A - VCE - SSCE Chemistry - Question 16 - 2016 - Paper 1
Step 1
A. The concentration of COCl\(_2\) would increase.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Heating an equilibrium system generally favors the endothermic direction if the reaction's enthalpy is known. COCl(_2) will not necessarily increase without understanding the balanced reaction.
Step 2
B. The total gas pressure in the flask would decrease.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
According to the ideal gas law, increasing the temperature at constant volume will actually increase the pressure, not decrease it.
Step 3
C. The equilibrium constant for the reaction would increase.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The equilibrium constant depends on temperature. For endothermic reactions, increasing temperature will increase the equilibrium constant of the system.
Step 4
D. The total number of gas molecules in the flask would increase.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The total number of gas molecules does not change simply due to increased temperature at constant volume; the stoichiometric relationships based on the reaction must be considered.