Four different flasks, A, B, C and D, at the same temperature, contain a mixture of PCl₃, PCl₅ and Cl₂ - VCE - SSCE Chemistry - Question 9 - 2008 - Paper 1
Question 9
Four different flasks, A, B, C and D, at the same temperature, contain a mixture of PCl₃, PCl₅ and Cl₂. The concentration, in mol L⁻¹, of these components in each of... show full transcript
Worked Solution & Example Answer:Four different flasks, A, B, C and D, at the same temperature, contain a mixture of PCl₃, PCl₅ and Cl₂ - VCE - SSCE Chemistry - Question 9 - 2008 - Paper 1
Step 1
Identify the equilibria condition
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Answer
To determine the flask that is not at equilibrium, we first need to analyze the fundamental equilibrium expression for the chemical reaction involving PCl₃, PCl₅, and Cl₂. Assuming a general equilibrium reaction:
PCl3+Cl2⇌PCl5
The equilibrium constant expression can be formulated as:
Kc=[PCl3][Cl2][PCl5]
Step 2
Calculate $K_c$ for each flask
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Next, we calculate the value of Kc for each flask using the concentrations provided:
Flask A:Kc=0.15×0.300.20=0.0450.20≈4.44
Flask B:Kc=0.20×0.150.15=0.030.15=5.00
Flask C:Kc=0.10×0.400.40=0.040.40=10.00
Flask D:Kc=0.30×0.150.80=0.0450.80≈17.78
Step 3
Determine which flask is not at equilibrium
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Answer
We compare these Kc values to find anomalies.
Using the ratios calculated, if any of the flasks shows a deviation from these constant values, it indicates that it is not at equilibrium.
Comparing the ratios:
Flask A: 4.44
Flask B: 5.00
Flask C: 10.00
Flask D: 17.78
The least concentration of [Cl2] in Flask B indicates that the gas mixture is shifting towards producing reactants, making Flask B the mixture not at equilibrium.