In solution, pale yellow-coloured Fe³⁺(aq) and colourless SCN⁻(aq) form an equilibrium with FeSCN²⁺(aq) - VCE - SSCE Chemistry - Question 6 - 2006 - Paper 1
Question 6
In solution, pale yellow-coloured Fe³⁺(aq) and colourless SCN⁻(aq) form an equilibrium with FeSCN²⁺(aq). FeSCN²⁺(aq) is red in colour.
Fe³⁺(aq) + SCN⁻(aq) ⇌ FeSCN²⁺... show full transcript
Worked Solution & Example Answer:In solution, pale yellow-coloured Fe³⁺(aq) and colourless SCN⁻(aq) form an equilibrium with FeSCN²⁺(aq) - VCE - SSCE Chemistry - Question 6 - 2006 - Paper 1
Step 1
Sample 1: 1 drop of a concentrated solution of Ag⁺(aq) is added, which forms a AgSCN precipitate.
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Answer
I. Colour will be less red since the equilibrium shifts left to compensate for the removal of SCN⁻.
II. The concentration of [Fe³⁺] will decrease as the reaction shifts left.
Step 2
Sample 2: 1 drop of a concentrated solution of Fe³⁺(aq) is added.
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Answer
I. Colour will be more red as the increase in Fe³⁺ pushes the equilibrium to the right.
II. The concentration of [Fe³⁺] will increase due to the additional Fe³⁺ added.
Step 3
Sample 3: 1 drop of a concentrated solution of HPO₄²⁻(aq) is added, which forms colourless FeHPO₄(aq).
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Answer
I. Colour will be less red since the equilibrium shifts left due to decreased Fe³⁺ availability.
II. The concentration of [Fe³⁺] will decrease as some Fe³⁺ reacts to form FeHPO₄.
Step 4
Sample 4: Addition of a large volume of water.
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Answer
I. Colour will be less red as dilution reduces the concentration of all species.
II. The concentration of [Fe³⁺] will decrease due to dilution.
Step 5
b. Sketch the changes that would be expected to occur to these concentrations if the temperature of the equilibrium mixture was increased.
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Answer
As the reaction is exothermic, increasing the temperature will shift the equilibrium to the left, favoring the reactants. Therefore, the concentrations would show a decrease in [FeSCN²⁺] and an increase in both [Fe³⁺] and [SCN⁻], illustrated as: