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The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation HOCl(aq) + H⁺(aq) + Cl⁻(aq) ⇌ Cl₂(aq) + H₂O(l) Which of the following, when added to a solution of NaOCl, would not raise the concentration of Cl₂ in the solution? A - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1
Question 16
The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation HOCl(aq) + H⁺(aq) + Cl⁻... show full transcript
Worked Solution & Example Answer:The HOCl produced in a solution of NaOCl can react further to produce small amounts of chlorine, Cl₂(aq), in water according to the equation HOCl(aq) + H⁺(aq) + Cl⁻(aq) ⇌ Cl₂(aq) + H₂O(l) Which of the following, when added to a solution of NaOCl, would not raise the concentration of Cl₂ in the solution? A - VCE - SSCE Chemistry - Question 16 - 2004 - Paper 1
Step 1
Which of the following, when added to a solution of NaOCl, would not raise the concentration of Cl₂ in the solution?
Answer
To determine which of the options does not increase the concentration of Cl₂ in the solution, we analyze each choice:
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NaCl: This adds Cl⁻ ions to the solution, which could participate in the reaction and potentially increase Cl₂ concentration.
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NaOH: This is a strong base that can increase the pH of the solution, which may lead to a decrease in the formation of Cl₂, as less HOCl is present in basic conditions.
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H₂SO₄: This strong acid would increase the concentration of H⁺ ions, promoting the formation of Cl₂ from the existing HOCl since it shifts the equilibrium to the right.
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HOCl: Adding more HOCl would facilitate the production of Cl₂, thus increasing its concentration.
Based on the analysis, the option that would not raise the concentration of Cl₂ in the solution is B. NaOH.