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Hydrogen and chlorine react according to the equation $$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$ 3 mole of H$_2$, and 2 mole of Cl$_2$, are placed in a vessel and sealed - VCE - SSCE Chemistry - Question 10 - 2005 - Paper 1

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Hydrogen and chlorine react according to the equation $$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$ 3 mole of H$_2$, and 2 mole of Cl$_2$, are placed in a vessel and se... show full transcript

Worked Solution & Example Answer:Hydrogen and chlorine react according to the equation $$H_2(g) + Cl_2(g) \rightarrow 2HCl(g)$$ 3 mole of H$_2$, and 2 mole of Cl$_2$, are placed in a vessel and sealed - VCE - SSCE Chemistry - Question 10 - 2005 - Paper 1

Step 1

Determine the Reaction Stoichiometry

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Answer

According to the balanced chemical equation, the ratio of hydrogen to chlorine is 1:1, which means 1 mole of H2_2 reacts with 1 mole of Cl2_2 to produce 2 moles of HCl.

Step 2

Calculate the Moles of HCl Produced

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Answer

Given that we have 3 moles of H2_2 and 2 moles of Cl2_2, H2_2 is the limiting reactant. Therefore, 3 moles of H2_2 will produce 6 moles of HCl.

Step 3

Identify Remaining Reactants

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Answer

Since 3 moles of H2_2 react with 3 moles of Cl2_2, we will consume all the H2_2 and only 1 mole of Cl2_2 will remain unreacted.

Step 4

Final Composition of the Vessel

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Answer

When the reaction is complete, the vessel will contain 6 moles of HCl and 1 mole of Cl2_2. Hence, the correct answer is D.

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